Answer:
22.29% probability that both of them scored above a 1520
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.
So



has a pvalue of 0.5279
1 - 0.5279 = 0.4721
Each students has a 0.4721 probability of scoring above 1520.
What is the probability that both of them scored above a 1520?
Each students has a 0.4721 probability of scoring above 1520. So

22.29% probability that both of them scored above a 1520
Answer:
s inversely proportional 1/t
s=0.3, t=8
s=k/t
0.3=k/8
k=0.3×8
k=2.4
find s when t=0.4
s=2.4/0.4
s=6.0 or 6
Answer:
A: 9 is subtracted from the product of 5 and a number.
Step-by-step explanation:
We know this because when a varible is place directly next to a number then the number is being multiplied by an unknow number. So in this equation five is being multiplied by an unknown number and nine is being subtracted from that.
Answer:
(1, 1 )
Step-by-step explanation:
Given the 2 equations
2x + 3y = 5 → (1)
7x - 5y = 2 → (2)
Multiplying (1) by 5 and (2) by 3 and adding will eliminate the y- term
10x + 15y = 25 → (3)
21x - 15y = 6 → (4)
Add (3) and (4) term by term to eliminate y
31x = 31 ( divide both sides by 31 )
x = 1
Substitute x = 1 into either of the 2 equations and evaluate for y
Substituting into (1)
2(1) + 3y = 5
2 + 3y = 5 ( subtract 2 from both sides )
3y = 3 ( divide both sides by 3 )
y = 1
Solution is (1, 1 )