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3 years ago

Find the area of the shape shown below.

Mathematics

2 answers:

Artyom0805 [142]3 years ago

7 0

Answer is 40 um have a great day!

SCORPION-xisa [38]3 years ago

4 0

The correct is 40 hope I helped

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The closer the slope value is to zero, the steeper the line. yes or no

Harrizon [31]

No, that is not true. Use the website desmos.com to try it out yourself. Graph equations like y=1x, y=1/2x, and y=1/4x to try. Then, you will see that as the number gets bigger, the line gets steeper (it gets higher..like a hill..rising..)

7 0

3 years ago

How do I do this please help!

jeka94

Answer:

put the 4x on the top and the negative 3 on the left not the bottom

6 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Readme [11.4K]

Answer:

3/11

Step-by-step explanation:

Divide both the numerator and denominator by 2.

$\dfrac{6}{22}=\dfrac{2*3}{2*11}=\dfrac{3}{11}$

8 0

2 years ago

Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting

stealth61 [152]

Answer:

Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$ and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

Thus, Anna's walk as a vector representation is $80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}$

7 0

2 years ago

Read 2 more answers

Find the nth term of: 11, 18, 37, 74, 135

storchak [24]

The nth term is 6n^2-11n+16

6 0

2 years ago