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3 years ago

Find the mean, median, and mode of the data set. Round to the nearest tenth. 15, 1, 4, 4, 8, 7, 15, 4, 15, 4, 5

Mathematics

1 answer:

Maksim231197 [3]3 years ago

6 0

Answer:

Median: 4.5

Mode: 4

Mean: 6.7

Step-by-step explanation:

First lets find the median, the number in the middle. To do this we need to put this data set in ascending order

1,4,4,4,4,5,7,8,15,15

The two numbers in the middle are 4 and 5. Now we must add these two numbers together and then divide by 2.

$\frac{4+5}{2} =\frac{9}{2} =4.5$

Nexte lets find the mode, the number that occurs the most. 4 appears 4 times, which is the greatest amount.

Now lets find the mean. First we need to find the sum of these 10 numbers

$1+4+4+4+4+5+7+8+15+15=67$

Next we have to divide by the number of data points, which is 10

$\frac{67}{10} =6.7$

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3 years ago

Read 2 more answers

Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0

3 years ago