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4 years ago

Find the mean, median, and mode of the data set. Round to the nearest tenth. 15, 1, 4, 4, 8, 7, 15, 4, 15, 4, 5

Mathematics

1 answer:

Maksim231197 [3]4 years ago

6 0

Answer:

Median: 4.5

Mode: 4

Mean: 6.7

Step-by-step explanation:

First lets find the median, the number in the middle. To do this we need to put this data set in ascending order

1,4,4,4,4,5,7,8,15,15

The two numbers in the middle are 4 and 5. Now we must add these two numbers together and then divide by 2.

$\frac{4+5}{2} =\frac{9}{2} =4.5$

Nexte lets find the mode, the number that occurs the most. 4 appears 4 times, which is the greatest amount.

Now lets find the mean. First we need to find the sum of these 10 numbers

$1+4+4+4+4+5+7+8+15+15=67$

Next we have to divide by the number of data points, which is 10

$\frac{67}{10} =6.7$

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If a student is 65.0 in tall, what is her height in m? (2.54 cm = 1 inch)

spayn [35]

Answer:

Height of the student=1.651m

Step-by-step explanation:

Given: Height of a student= 65.0 inch.

To find: Height of a student in meters.

Solution:

We know that 1 inch=2.54 cm, then

65.0 inch will be = $2.54{\times}65.0$

65.0 inch will be= $165.2 cm$

Also, we know that 1cm= $\frac{1}{100} m$ , then

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3 years ago

Rectangle J’K’L’M’ shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie

7nadin3 [17]

The answer is C. (16, 7)

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3 years ago

Last year, 50% of MNM. Inc. employees were female. It is believed that there has been a reduction in the percentage of females i

Serhud [2]

Answer:

We conclude that there has been a significant reduction in the proportion of females.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 400

p = 50% = 0.5

Alpha, α = 0.05

Number of women, x = 118

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.50\\H_A: p < 0.50$

This is a one-tailed test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{118}{400} = 0.45$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.45-0.50}{\sqrt{\frac{0.50(1-0.50)}{400}}} = -2$

Now, we calculate the critical value.

Now, $z_{critical} \text{ at 0.05 level of significance } = -1.645$

Since the calculated z-statistic is less than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, there has been a significant reduction in the proportion of females.

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3 years ago