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dedylja [7]
3 years ago
11

F(x)=x^2+1, (4,17) find slope

Mathematics
1 answer:
labwork [276]3 years ago
7 0

Answer:

ITS NOT A LINEAR EQUATION SO IT DOES NOT HAVE A SLOPE

Step-by-step explanation:

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4 0
3 years ago
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

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2 years ago
What are the domain and range of<br> g(x) = -2(x – 10)2 + 12?
disa [49]

Answer:

17

Step-by-step explanation:

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2 years ago
Use the distributive property to simplify this expression: negative 2 (3 x + x minus 5). 1. Using order of operations, combine l
sashaice [31]

Answer:

8x-10

Step-by-step explanation:

2x3x=6x, 2 x x=2x, 2x-5=-10 so 6x+2x-10= 8x-10

5 0
3 years ago
Read 2 more answers
Side of a rhombus is 5cm.if the lengthof one diagnol is 8cm,find the other
TEA [102]

Answer: the others are 5cm and 8cm


Step-by-step explanation:

this is because a rhombus is the same as a rectangle or square and they have equal two sides


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3 years ago
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