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earnstyle [38]
2 years ago
11

Determina el centro,radio y gráfica de la circunferencia:(x+2)2 + (y-3)2=121

Mathematics
1 answer:
Sergeu [11.5K]2 years ago
6 0

Answer:

La ecuación genérica para un círculo centrado en el punto (a, b), de radio R, es:

(x - a)^2 + (x - b)^2 = R^2

Entonces si miramos a nuestra ecuación:

(x + 2)^2 + (y - 3)^2 = 121

Tendremos el centro en:

(-2, 3)

el radio está dado por:

R^2 = 121

R = √121 = 11

La gráfica de esta circunferencia se puede ver en la imagen de abajo.

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Step-by-step explanation:

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If k-9=5(k-3)find k​
jok3333 [9.3K]

Answer:

K = 3/2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

k−9=5(k−3)

k+−9=(5)(k)+(5)(−3)(Distribute)

k+−9=5k+−15

k−9=5k−15

Step 2: Subtract 5k from both sides.

k−9−5k=5k−15−5k

−4k−9=−15

Step 3: Add 9 to both sides.

−4k−9+9=−15+9

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Step 4: Divide both sides by -4.

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K = 3/2

7 0
3 years ago
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The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.
lora16 [44]

Answer:

The standard form as y=5x^2+30x+41

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of

Given y = 5(x+3)^2-4

Squaring  using (a+b)^2=a^2+b^2+2ab , we get,  

y=5(x^2+9+6x)-4

Multiply 5 inside , we get,

y=5x^2+45+30x-4

Solving further , we get,

y=5x^2+30x+41

Thus , we have obtained the standard form as y=5x^2+30x+41







8 0
3 years ago
Read 2 more answers
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