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3 years ago

Like this is this correct or wrong

Mathematics

2 answers:

NikAS [45]3 years ago

8 0

Answer:

move the blue rectangle when the blue rectangle's bottom left corner meets the bottom left corner of the grid

Step-by-step explanation:

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

anastassius [24]3 years ago

3 0

Answer:

no, the bottom left corner of the blue rectangle has to be on point (0,0)

Step-by-step explanation:

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A survey was conducted on a random sample of 100

zalisa [80]

Answer:

No, he is not correct because red and yellow got the same amount of votes when it came to adding them up.

Step-by-step explanation:

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2 years ago

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If a jogger runs 2 miles and burns 185 calories, how many calories would he burn if he jogged 3 miles?

aliina [53]

The total amount of calories burnt in jogging 2 miles = 185 calories

We have to determine the number of calories burned in jogging 3 miles.

Firstly, we will determine the amount of calories burnt in jogging 1 mile. We will use unitary method to evaluate this.

So, the total amount of calories burnt in jogging 1 mile = $185 \div 2$

= 92.5 calories

So, the amount of calories burnt in 3 miles = $3 \times 92.5$

= 277.5 calories

Therefore, 277.5 calories are burned in jogging 3 miles.

6 0

3 years ago

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Consider the relation y = −8|x + 3| − 9. what are the coordinates of the vertex? (−3, 9) (−3, −9) (3, −9) (3, 9)

german

By simple substitution on the left side and on the right side of the given equation, we have to
For coordinates (-3,-9)
-9=−8|-3+3|−9
-9=−8|0|−9
 -9=−9
Therefore, it is demonstrated that the coordinates of the vertex is
(-3,-9)

7 0

3 years ago

Evaluate 13+6 over y when y=6

Zepler [3.9K]

Answer:19/6

Step-by-step explanation:

you would first get 13+6/6

Which is 19/6 when you add 13 +6 then divide by 6

6 0

3 years ago

Let a, b, c and x elements in the group G. In each of the following solve for x in terms of a, b, and c.

Nezavi [6.7K]

Answer:

$x=c.a^{-1}.b^{-1}$

Step-by-step explanation:

Given equation,

$axb = c-----(1)$

$(axb) ( a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})$

$(xb)(a)(a^{-1}.b^{-1} ) = c.(a^{-1}b{-1})$ ( commutative law of multiplication )

$(xb)(a.a^{-1}).b^{-1} = c.a^{-1}b{-1}$ ( Associative property )

$(xb).e.b^{-1} = c.a^{-1}b{-1}$

$(xb).b^{-1}=c.a^{-1}.b^{-1}$ ( identity property )

$x.(b.b^{-1})=c.a^{-1}.b^{-1}$ ( Associative property )

$x.e=c.a^{-1}.b^{-1}$

$x=c.a^{-1}.b^{-1}$ ( identity property )

5 0

3 years ago