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lakkis [162]
3 years ago
13

How do I get area pls help

Mathematics
2 answers:
viva [34]3 years ago
5 0

Finding Area varies based on what you are trying to find.

Area of a triangle is 1/2(Base)(Height)

EX: B=10 , H= 15

A=1/2(10)(15)

A=5(15)

A=75^2

Area of a Square or rectangle is Length(Width)

EX: L=10 , W=15

A=10X15

A=150^2

Area of a circle is 3.14(Radius^2) or 3.14(Diameter)

R=10 , D=20

A= 3.14(10^2)

A=314

OR

A=3.14(20^2)

A=1256

cupoosta [38]3 years ago
3 0
Area of a square : One side x 2
Area of triangle : Width x Height then divide by 2
Area of <span>parallelogram : Width x Height
Area of Trapizoid : base 1 x base 2 then divide by 2, next multiply times the height

I'm pretty sure that all you need to know since this is an elementry school question.
</span>
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The numerical value of the variance a. is negative if the mean is negative. b. is always larger than the numerical value of the
Snowcat [4.5K]

Answer:

Step-by-step explanation:

Variance is the sum of squares of all items x from mean.  i.e

Variance = \Sigma (x-xbar)^2

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8 0
3 years ago
Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)​
umka2103 [35]

Answer:

<u>GIVEN :-</u>

  • ∠A = 15°
  • Length of AB (hypotenuse) = 60 ft

<u>TO FIND :-</u>

  • Length of BC
  • Length of AC
  • Area of ΔABC

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}

<u>SOLUTION :-</u>

In ΔABC ,

  • \sin 15 = \frac{BC}{60}

=> 0.2588... = \frac{BC}{60}

=> BC = (0.2588....) \times 60 = 15.5291..... ≈ 15.5 ft

  • \cos 15 = \frac{AC}{60}

=> 0.9659..... = \frac{AC}{60}

=> AC = (0.9659.....) \times 60 = 57.9555..... ≈ 58 ft

Area of ΔABC = \frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2

4 0
2 years ago
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