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3 years ago

Is 3.7 an integer Need help on my math homework plz help

Mathematics

1 answer:

Finger [1]3 years ago

4 0

An integer is a number that is not a fraction so no 3.7 is not an integer

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At which values of x does the function F(x) have a vertical asymptote? Check

Vaselesa [24]

Answer:

x=0, x= - 3, x=9

Step-by-step explanation:

f(x)=7/2x(x+3)(x-9)

f(x) doesn't exist for x=0,-3,9

$\lim_{x \to \ 0,-3,9} f(x) = inf$

vertical asymptote:

x=0, x= - 3, x=9

3 0

3 years ago

Angle XYZ = 2X° and angle PQR = (8X -20)°. If angle XYZ and angle PQR are supplementary, find the measure of each angle. Angle P

Alchen [17]

Answer:

$PQR = 140$

Step-by-step explanation:

Given

$XYZ = 2X$

$PQR = 8X - 20$

Required

Find PQR

Since both angles are supplementary, we have:

$XYZ + PQR = 180$

This gives:

$2X + 8X - 20 = 180$

$10X - 20 = 180$

Collect Like Terms

$10X = 20 + 180$

$10X = 200$

Divide through by 10

$X = 20$

Substitute 20 for X in $PQR = 8X - 20$

$PQR = 8 * 20 -20$

$PQR = 140$

7 0

3 years ago

two planes take off at a new york airport. the first plane climbs at an angle of 45 degree with respect to the ground amd reache

vaieri [72.5K]

The answer is fully given in the picture below. Hope it helps!

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Kitty [74]

Answer: (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

y - intercept = (0, 1) 2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

$y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\$

vertex = (1, -4) 2nd point (y-intercept) = (0, -3)

<em>see attached</em> - the graphs intersect at two points: (-2, 5) and (2, -3)

8 0

3 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

3 0

4 years ago