(For full answer you might have to go to the comments)
Answer: 28x+30
Explanation: we divide (3x^3-2x^2+4x-3) by (x^2+3x+3) Using long division
3x-11
___________________
(x^2+3x+3) 3x^3-2x^2+4x-3
-(3x^3+9x^2+9x)
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-11x^2-5x-3
-(-11x^2-33x-33)
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28x+30
So our remainder will be 28x+30
Y-(-2)= -2/3(x-6)
3y+6= -2x +12
2x +3y +6=0
I think D is the correct answer
Answer:wdym?
Step-by-step explanation: