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2 years ago

3. -4r – 6 + 6r + 9 = 29

Mathematics

2 answers:

SIZIF [17.4K]2 years ago

8 0

Answer:

r=13

Step-by-step explanation:

Brums [2.3K]2 years ago

4 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Step-by-step explanation:

You might be interested in

How to find n for F=n/4+37

Alla [95]

Answer: F=40 or other words n=40

Step-by-step explanation:

F= n/4 + 37

F= 12/4 + 37

F= 3 +37

F =40

Hope this helped! ;)

3 0

2 years ago

PLS answer quick

Stolb23 [73]

The formula to find the volume of the composite solid is: C. V = πr²h + ⅔πr³.

<h3>How to Find the Volume of a Composite Solid?</h3>

The volume of the composite solid in the image given = Volume of cylinder + volume of hemisphere.

Volume of cylinder = πr²h

Volume of hemisphere = ⅔πr³

Therefore, formula to find the volume is: C. V = πr²h + ⅔πr³.

Learn more about volume of composite solid on:

brainly.com/question/23642076

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7 0

1 year ago

A store buys 17 sweaters for $204 and sells them for $646. how much profit does the store make per sweater?

uranmaximum [27]

Total profit: 646 - 204 = 442

profit per shirt = 442 / 17 = 26

Answer: $26

6 0

2 years ago

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .