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3 years ago

What are the zeroes of the function?

Mathematics

1 answer:

WINSTONCH [101]3 years ago

4 0

Answer:

Option C

Step-by-step explanation:

x - 3 = 0

Add 3 to both sides;

x = 3

x + 2 = 0

Subtract 2 from both sides;

x = -2

x - 2 = 0

Add 2 to both sides;

x = 2

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What is the greatest common factor of 10, 20, and 50?

Viefleur [7K]

Answer:

Step-by-step explanation:

first you need to find the prime factors of the three numbers

ex:

prime factor of 18= $2*3*3$

prime of 24= $2*2*2*3$

there is one 2 and one 3 in common

greatest common multiple 2*3=6

so the greatest common multiple is ten because it is the only one that can divide between all three evenly.

$10=10/10=1\\20=20/10=2\\50=50/10=5$

so 10 is your answer

6 0

3 years ago

David leaves reading at 11 45am. he arrives at cardiff at 1 45pm. david drives at an average speed of 56 miles per hour. work ou

yan [13]

Step-by-step explanation:

speed = distance/time

we know the speed and the time (11:45am to 1:45pm = 2 hours).

distance = speed × time = 56 m/h × 2 h = 112 miles

3 0

2 years ago

Which pairs make the equation x-9y=12 true

Serggg [28]

Answer:

(12,0), (3, -1) (0,-4/3)

Step-by-step explanation:

To do this problem, you have to plug in the x and y values. For example, the first one would be 12-9(0)=12, and so on.

6 0

3 years ago

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$

Probability of getting second prize is $\frac{2}{20000}$

Probability of getting third prize is $\frac{20}{20000}$

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

$\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10$

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is $\frac{19977}{20000}$

The expected value is

$E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25$

$E=\frac{1000+600+200-4994.25}{20000}$

$E=\frac{-3194.25}{20000}$

$E=-0.159$

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0

3 years ago

F(x)=3x-4 and g(x) = x2 find the value of f(3)-g(2) <br><br> show all work

zheka24 [161]

Answer: 1

f(x) = 3x - 4 => f(3) = 3.3 - 4 = 9 - 4 = 5

g(x) = x² => g(2) = 2² = 4

=> f(3) - g(2) = 5 - 4 = 1

Step-by-step explanation:

3 0

3 years ago