<span>Use the Pythagorean Theorem to solve. This will be a right triangle:
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Let the slope = the hypotenuse = c
Let one side = a=8
Let the other side =b =15
Plug-in the values and solve for the c-term
Check you answer by plugging the value of "c" back into the orignial equation and solve.
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17=c
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Check by plugging into the original equation and solve.
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289=289 [checks out]</span>
Answer:
7.6
Step-by-step explanation:
From the graph, we know the lengths of two legs.
a = 3
b = 7
Knowing this, we can use the Pythagorean Theorem to solve for c, the hypotenuse. (remember, a^2 + b^2 = c^2)
c = √a2 + √b2
= √(7)2 + √(3)2
= √49 + √9
= √58
= 7.6
Answer:
C. Black grapes cost more per pound than green grapes.
Step-by-step explanation:
<em>Verify each statement</em>
A. Three pounds of green grapes cost $6.00
The statement is False
Because
For x=3 pounds
y=1.5x
y=1.5(3)=$4.5
B. Black grapes cost less per pound than green grapes
The statement is False
Because
For x=1 pound
The green grapes cost ----> y=1.5(1)=$1.5
Observing the graph
For x=1 pound
The black grapes cost $2
C. Black grapes cost more per pound than green grapes.
The statement is True
D. Two pounds of black grapes cost $3.00.
The statement is False
Because
Observing the graph
Two pounds of black grapes cost $4
Answer:
x = 21
Step-by-step explanation:
To see for what value of x is the equation true, we have to solve x.
![\displaystyle \frac{2}{3} x - 3 = 11\\\\Adding \ 3 \ to \ both \ sides\\\\\frac{2x}{3} = 11 + 3\\\\\frac{2x}{3} = 14\\\\Multiply \ 3 \ to \ both \ sides\\\\2x = 14 \times 3\\\\2x = 42 \\\\Divide\ both\ sides\ by\ 2\\\\x = 42/2\\\\x = 21\\\\For \ x = 21\ the \ given \ equation \ is \ true.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%7D%7B3%7D%20x%20-%203%20%3D%2011%5C%5C%5C%5CAdding%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2011%20%2B%203%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2014%5C%5C%5C%5CMultiply%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C2x%20%3D%2014%20%5Ctimes%203%5C%5C%5C%5C2x%20%3D%2042%20%5C%5C%5C%5CDivide%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%5C%5Cx%20%3D%2042%2F2%5C%5C%5C%5Cx%20%3D%2021%5C%5C%5C%5CFor%20%5C%20x%20%3D%2021%5C%20the%20%5C%20given%20%5C%20equation%20%5C%20is%20%5C%20true.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>