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2 years ago

Which value of x makes the equation 2/3x-3=11 true?

Mathematics

1 answer:

harkovskaia [24]2 years ago

7 0

Answer:

x = 21

Step-by-step explanation:

To see for what value of x is the equation true, we have to solve x.

$\displaystyle \frac{2}{3} x - 3 = 11\\\\Adding \ 3 \ to \ both \ sides\\\\\frac{2x}{3} = 11 + 3\\\\\frac{2x}{3} = 14\\\\Multiply \ 3 \ to \ both \ sides\\\\2x = 14 \times 3\\\\2x = 42 \\\\Divide\ both\ sides\ by\ 2\\\\x = 42/2\\\\x = 21\\\\For \ x = 21\ the \ given \ equation \ is \ true.\\\\\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Please please please help. thank you.

djverab [1.8K]

Lets get started :)

The First question:
Diameter = 20 ft
Radius = $\frac{1}{2}$ of 20 (diameter) = 20 ft

Area formula of a circle is
A = $\pi$ r²
= $\pi$ (10)²
=100 $\pi$ ft²
≈ 314 ft²

The answer will be the second option

The Second question:
radius of circle = 12mm divided into 20 sectors area

A = $\pi$ r²
= $\pi$ (12)²
= 144 $\pi$ ft²

Divide into 20 equal sector areas = $\frac{144 \pi }{20} = 7.2 \pi$

≈ 22.6 mm²

Your answer will be the third option

The Third Question:

90°, sector area = 36 $\pi$ , Radius = ?

$\frac{angle}{360} = \frac{sector}{ \pi (r)^2}$
$\frac{90}{360} = \frac{36 \pi }{ \pi r^2}$
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We can now cross multiply
360 × 36 = 90r²
12960 = 90r²

Divide by 90 on either side

$\frac{12960}{90} = \frac{90r^2}{90}$
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Your answer will be the third option

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3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

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3 years ago

I don’t really understand this please help ! :) thanks

taurus [48]

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Step-by-step explanation: because on the first on it added by 7 so you would have to do the same for all of them.

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3 years ago