3x2+4x=2
6+4x=2
-6 -6
4x=-4
4 4
x=-1
If the original number is ab it has a value of
10a+b when it is reversed it will have a value of 10b-a
10b+a-10a-b is the differences which is equal to
9b-9a
So the numbers must be divisible by 9
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Answer:
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Answer:
64a³c²⁷
Step-by-step explanation:
The expression inside parentheses can be simplified by noting that b^0 = 1. Then you have ...
(4ac^9)^3
The rules of exponents say the exponent outside applies to each of the inside factors. For c^9, the exponents multiply.
Here are the applicable rules:
(ab)^c = (a^c)(b^c)
(a^b)^c = a^(b·c)
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(4ac^9)^3 = 4^3·a^3·c^(9·3) = 64a^3c^27