Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Answer:
The intensity of the first earthquake is 6.31 times the second one
Step-by-step explanation:
The given formulae is M=log(
)
Here for both the earthquakes the value of S is same.
Let the Intensity of the first earthquake be I1 and the second be I2.
Given M1=7.5
M2=6.7
Now M1=log(
)------1
M2=log(
)-----2
Now subtract 1 and 2 we get
M1-M2=log(
)
I1/I2=
I1=I2(
I1=I2*6.31
Answer:
If Tim actually earned 62 points . Therefore Tim's percent error is 58.1 % .
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
AE=EC
5x-10=2x+5
5x-2x=5+10
3x=15
x=5
Answer:
it would have snowed 1 2/5 feet more the previous day than the current day.