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3 years ago

13

Which expression best estimates 6 and three-fourths divided by 1 and two-thirds? 7 divided by 2 6 divided by 1 8 divided by 3 3

divided by 2

2 answers:

Elodia [21]3 years ago

6 0

Answer:

$4\frac{1}{20}$

Step-by-step explanation:

$6\frac{3}{4} \div 1\frac{2}{3}$

$\frac{27}{4} \div \frac{5}{3}$

$\frac{27}{4} \times \frac{3}{5}$

$\frac{27 \times 3}{4 \times 5}$

$=\frac{81}{20}$

$=4\frac{1}{20}$

Elza [17]3 years ago

4 0

Answer:

7 divided by 2

Step-by-step explanation:

edge-

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Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving

lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

$P(x=0) = ^nC_x P^x (1-P)^n^-^x$

$P(x=0) = ^5C_0 (0.4)^0 (1-0.4)^5^-^0$

$P(x=0) = ^5C_0 (0.4)^0 (0.60)^5$

$P(x=0) = 0.778$

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

$= 1 - P(X = 0)$

$= 1 - ^5C_0 (0.4)^0 * (0.6)^5$

$= 1 - 0.0778$

$= 0.9222$

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

$^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 (0.4)^2 (0.6)^3$

$= 0.6826$

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

$= 1 - [^5C_0 (0.4)^0 (0.6)^5 + ^5C_1 (0.4)^1 (0.6)^4 + ^5C_2 * (0.4)^2 (0.6)^3]$

$= 1 - 0.6826$

$= 0.3174$

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

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Answer: 3/10 probability

Step-by-step explanation:

We are telling the probability with tenths, so we can say that the probability of the meteoroid landing on Earth is 3/10.

If the surface area of the world is approximately 7/10, or 70 percent, water, there is approximately 3/10, or 30 percent, chance of the meteoroid hitting land.

I'm pretty sure, at least ^_^

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3 years ago

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Answer:

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Step-by-step explanation:

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il63 [147K]

Answer:

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Step-by-step explanation:

Cross multiply, isolate the variable, and divide by the coefficient to solve.

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3 years ago