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jarptica [38.1K]
3 years ago
13

The two-way table represents data from a survey asking schoolchildren whether they are attending a summer camp, taking swimming

lessons, or both.
Which is the joint relative frequency for school children who plan to attend camp and have swimming lessons? Round the answer to the nearest percent.

4%
19%
33%
44%

Mathematics
2 answers:
amm18123 years ago
7 0
The joint relative frequency values are the top-left four squares, or the intersection of 2 variables, divided by the total number in the bottom-right corner, which is 96. 

Find the intersection of Camp and Swimming lessons. The number is 42. Divide this number by 96:
42 ÷ 96 = 43.75%

Best answer is 44%
stiks02 [169]3 years ago
3 0

Answer: Last option is correct.

Step-by-step explanation:

Since we have given that

Number of frequency for school children who plan to attend camp and have swimming lessons = 42

And total number of school children surveyed for this purpose = 96

So, Joint relative frequency for school children who plan to attend camp and have swimming lessons is given by

=\frac{\text{Number of students who takes swimming lessons and attend camp}}{\text{ Total number of students}}\\\\=\frac{42}{96}\times 100\\\\=43.75\%\\\\=44\%\ approximately

hence, Last option is correct.

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Which equation should be used to find the volume of the figure?
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Given that

                                                                 1

John can run 100 meters dash in 16    --------- seconds .

                                                                  5

Savanna 's time is 19.8 seconds .

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Converting mixed fraction into improper .

     1                      16 * 5     +  1                 80 + 1                 81

16  --------    =     ---------------------------    =   -------------- =   - -----------

    5                           5                                  5                      5

Thus we got John time as 81 /5 seconds .

Converting Savanna's time in fraction , we get

 19 8

----------  seconds .

  10  

We have two fractions with different denominator .

One is having denominator 5 and another is having denominator 10 .

We need to make the denominator same of both the fraction .

We need to make denominator 10 .

Multiply John fraction by 2 in both numerator and denominator by 2 to make denominator 10 .

81 * 2               162

----------  =      ------------ seconds .

5 *  2                   10

John is taking less time than Savanna . Thus John is faster .

Difference

198          162            36

-------  -     -------     =  ------- seconds  

10              10              10

Thus John is faster by  (36/10 ) seconds  =  3.6 seconds.

Step-by-step explanation:

Given that

                                                                 1

John can run 100 meters dash in 16    --------- seconds .

                                                                  5

Savanna 's time is 19.8 seconds .

Here we have John time in mixed fraction and Savanna's time in decimal .

Converting mixed fraction into improper .

     1                      16 * 5     +  1                 80 + 1                 81

16  --------    =     ---------------------------    =   -------------- =   - -----------

    5                           5                                  5                      5

Thus we got John time as 81 /5 seconds .

Converting Savanna's time in fraction , we get

 19 8

----------  seconds .

  10  

We have two fractions with different denominator .

One is having denominator 5 and another is having denominator 10 .

We need to make the denominator same of both the fraction .

We need to make denominator 10 .

Multiply John fraction by 2 in both numerator and denominator by 2 to make denominator 10 .

81 * 2               162

----------  =      ------------ seconds .

5 *  2                   10

John is taking less time than Savanna . Thus John is faster .

Difference

198          162            36

-------  -     -------     =  ------- seconds  

10              10              10

Thus John is faster by  (36/10 ) seconds  =  3.6 seconds.

4 0
3 years ago
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