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jarptica [38.1K]
4 years ago
13

The two-way table represents data from a survey asking schoolchildren whether they are attending a summer camp, taking swimming

lessons, or both.
Which is the joint relative frequency for school children who plan to attend camp and have swimming lessons? Round the answer to the nearest percent.

4%
19%
33%
44%

Mathematics
2 answers:
amm18124 years ago
7 0
The joint relative frequency values are the top-left four squares, or the intersection of 2 variables, divided by the total number in the bottom-right corner, which is 96. 

Find the intersection of Camp and Swimming lessons. The number is 42. Divide this number by 96:
42 ÷ 96 = 43.75%

Best answer is 44%
stiks02 [169]4 years ago
3 0

Answer: Last option is correct.

Step-by-step explanation:

Since we have given that

Number of frequency for school children who plan to attend camp and have swimming lessons = 42

And total number of school children surveyed for this purpose = 96

So, Joint relative frequency for school children who plan to attend camp and have swimming lessons is given by

=\frac{\text{Number of students who takes swimming lessons and attend camp}}{\text{ Total number of students}}\\\\=\frac{42}{96}\times 100\\\\=43.75\%\\\\=44\%\ approximately

hence, Last option is correct.

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Answer:

12) x = 10 or x = -10

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15)  n = 0 or -2

Step-by-step explanation:

12) Given, 4|x| + 3 = 43

Now, for x ≥ 0, |x| = x and for x < 0, |x| = -x

So, for x ≥ 0, the equation becomes 4x + 3 = 43

⇒ 4x = 40

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Therefore, the solution of the equation is x = 10 or x = -10. (Answer)

13) Given, 3|b| + 5 = 14

Now, for b ≥ 0, |b| = b and for b < 0, |b| = -b

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14) 9|2r - 4| + 1 = 73

Now, for 2r - 4 ≥0 i.e. r ≥ 2, then

9(2r - 4) + 1 = 73

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9(4 - 2r) + 1 = 73

⇒ 4 - 2r = 8

⇒ 2r = - 4

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15) For, 10n + 10 ≥ 0 i.e. n ≥ -1, then

1 + 4(10n + 10) = 41

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