Answer:
option B
3
Step-by-step explanation:
Given in the question an expression
Whole numbers are positive numbers, including zero, without any decimal or fractional parts.
Possible range of domain will be 1 ≤ x ≤ 48
We know that perfect square between 1 and 48 are
1 , 4 , 16 , 25 , 36
1)
x = 3
√48/3 = √16 = 4
2)
x = 12
√48/12 = √4 = 2
3)
x = 48
√48/48 = √1 = 1
#3.
in this case, all you need to do is to look at the intersecting point. each units represent 2, the coordinates of the intersection are (4,-1), so D is the choice.
#4. B is the choice. two lines either intersect once (one solution), never (parallel, no solution), or overwrap (merge, infinite solutions)
Answer:
Explained below.
Step-by-step explanation:
Convenience sampling is a kind of non-probability-sampling (i.e. all items doesn’t have an equivalent chance of being selected), which doesn’t comprises of random collection of items.
Convenience sampling is where we take in items which are easy to reach. This sort of sampling technique results in a biased sample.
Systematic sampling is a kind of probability sampling method in which individuals from a larger population are nominated according to a random initial point and a static, periodic interval. If the individual <em>k</em> is selected as the first sample then the sample space consists of every <em>k</em>th individual.
In this case the first sample is an example of convenience sample and the second is a systematic sample.
Answer:
In 6 different ways can the three students form a set of class officers.
Step-by-step explanation:
There are 3 people Leila, Larry, and Cindy and 3 positions president, vice-president, and secretary.
We need to find In how many different ways can the three students form a set of class officers.
This problem can be solved using Permutation.
nPr = n!/(n-r)! is the formula.
Here n = 3 and r =3
So, 3P3 = 3!/(3-3)!
3P3 = 3!/1
3P3 = 3*2*1/1
3P3 = 6
So, in 6 different ways can the three students form a set of class officers.
