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Nat2105 [25]
3 years ago
9

A car is travelling at 40 mph How long will it take this car to travel 130 miles?

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

Answer:

3.25 hours

Step-by-step explanation:

if the car is going 40mph then devide 130 by 40 to get the amount of time. that's how I was taught in school, sorry if it's wrong.

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4) Dan had 199 dollars to spend on 7 books. After
IRINA_888 [86]

Answer:

The answer is that each book costs 26 dollars

Step-by-step explanation:

First we subtract 199 dollar from 7 =182

Then we divide 182 dollars to the seven book in order to find a unit =182/7=26

To prove this answer multiply 26 dollars than 7 books and see if the outcome is 182.Then subtract 199 from 182 and see if you got 17.

3 0
3 years ago
Help please...........-
vovangra [49]

Answer:c

Step-by-step explanation:

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8 0
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If jerry runs 1\10 mile each day how many days will it take him to run 4\5 mile plz send walkthrough
guajiro [1.7K]
8 days because you multiply 1/10 x 8 = 8/10 after you simplify it you get 4/5 Hope it helped
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3 years ago
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Compare the function represented on the graph and the function modeled by y = 2/3 x .
Tpy6a [65]

Answer:

                                       

Step-by-step explanation:

3 0
3 years ago
Solve the equation on the interval [0,2π]
WARRIOR [948]
\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------

\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}

\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}
3 0
3 years ago
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