A) On the first place we can put 9 digits, on the second 9, on the third place 8 and on the last place 7 ( because no digits can be repeated ): 9 · 9 · 8 · 7 =4536 numbers b) There are 5 odd digits can be repeated. So: 5 · 10 · 10 · 5 = 2500 numbers c) On the first place we can put:5,6,7,8,9 (5 digits) On the last place is just one (0), because the number must be divisible by 10: 5 · 10 · 10 · 1 = 500 numbers d) on the first place we can put 2 digits ( 1, or 2 - there are no 4-digit numbers starting with 0). The last digit must be even, but the order can be: X - odd - odd - even 2 · 5 · 4 · 5 = 200 X - odd - even - even 2 · 5 · 5 · 4 = 200 X - even - odd - even 2 · 5 · 5 · 4 = 200 X - even - even - even 2 · 5 · 4 · 3 = 120 Finally: 200+ 200 + 200 + 120 = 720 numbers
