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kiruha [24]
3 years ago
14

Suppose f(π/3) = 3 and f '(π/3) = −7,

Mathematics
1 answer:
insens350 [35]3 years ago
8 0
Et's give this a go:h(x) = cos(x) / f(x)
derivative (recall the quotient rule)h'(x) = [ f(x) * (-sin(x)) - cos(x)*f'(x) ] / [ f(x) ]^2
simplifyh'(x) = [ -sin(x)*f(x) - cox(x)*f '(x) ] / [ f(x) ]^2h'(π/3) = [ -sin(π/3)*f(π/3) - cox(π/3)*f '(π/3) ] / [ f(π/3) ]^2h'(π/3) = −(3–√/2)∗(3)−(1/2)∗(−7)/(3)2
h'(π/3) = (−33–√/2+7/2)/9

And you can further simplify if you want, I'll stop there.
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A right triangle is a type of triangle which contains a right triangle. To be a right triangle, it should satisfy the Pythagorean Theorem which relates the three sides of the triangle. In this triangle, the longest side is called as the hypotenuse. To determine the hypotenuse, we use the Pythagorean Theorem which is expressed as follows:

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3 years ago
During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s . What was her average acceleration du
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Step-by-step explanation:

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The rate change of velocity per unit time is call the acceleration of the object.

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During the final 5 seconds of a race cyclist increased her velocity from 4m/s to 7 m/s

Here v= 7 m/s and u=4 m/s t=5 seconds

\therefore a=\frac{7\ m/s-4 \ m/s}{5s}

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The average acceleration of the cyclist was 0.6 m/s².

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Step-by-step explanation:

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<em>t would be 8 if you are multiplying .</em>
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