Hello from MrBillDoesMath!
Answer:
y = (2/3)x + 16
Discussion:
Given line:
2x - 3y = 6 => add 3y to both sides
2x = 6 + 3y => subtract 6 from both sides
2x -6 = 3y => divide both sides by 3
y =(2/3)x - 2
The slope of this line, m, (2/3) and any line parallel to the given line has the same slope. We are looking for the line with slope (2/3) passing through (-6, 12)
y = (2/3)x + b => substitute (x,y) = (-6, 12) in the equation
12 = (2/3)(-6) + b => add (2/3)(6) = 12/3 = 4
12 + 4 = (2/3)(-6) + (2/3)(6) + b => as (2/3)(-6) + (2/3)(6) = 0
12 +4 = 0 + b =>
b = 16
Hence the equation of the parallel line through ( -6,12) is
y = mx + b
=(2/3)x + 16
Check: is (-6,12) on this line? Does 12 = (2/3)(-6) + 16 = -4 + 16 = 12? Yes!
Thank you,
MrB
