Answer:
you bet
Step-by-step explanation:
The answer for this would be 0.06.
The answer is 0.154 m
Step 1. Calculate the volume of gasoline tank (V) using the known mass (m) and density of gasoline (D).
D = m/V
⇒ V = m/D
D = 719.7 kg/m³
m = 45.0 kg
V = 45.0 kg/719.7 kg/m³ = 0.0625 m³
Step 2. Calculate the depth of the tank (d) using the known volume (V) of gasoline and width (w) and length (l) of the tank:
V = d * w * l
0.0625 = d * 0.900 * 0.450
0.0625 = d * 0.405
d = 0.0625 / 0.405
d = 0.154 m
Step-by-step explanation:
MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]
WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)
SUBSTITUTING INTO THE EQUATION ABOVE
(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]
EQUATING THE X COORDINATES
=> 3 = (2+ X2)/2 (CROSS MULTIPLY)
=> 6 = 2 + X2
X(subscript 2)= 4
EQUATING THE Y COORDINATES
=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)
6 = –8 +Y2
=> Y(subscript 2)= 14
THEREFORE THE COORDINATES OF B ARE (4 ,14)
hope this helps :)
That function is incorrect.
The correct function is . . . . C(f) = (5/9) (f - 32) .
If a Fahrenheit thermometer reads 52° ,
then a Celsius thermometer should read . . .
C (52) = (5/9) (52 - 32) =
(5/9) (20) = <em>(11 and 1/9)°C</em>.
