Given :
The half life of Carbon-14 ,
.
Trace amounts of Carbon-14 1/2408 remains.
To Find :
How old is the rock .
Solution :
Let , initial concentration of Carbon-14 is C .
Quantity remains ,
.
Rate constant is :

By first order equation :
![kt=-ln(\dfrac{[A_t]}{[A_o]})\\\\t=-\dfrac{ln(\dfrac{[A_t]}{[A_o]})}{k}\\\\t=-\dfrac{ln(\dfrac{[A_o]}{[A_o]\times 2408})}{1.2\times 10^{-4}}\ years\\\\t=-\dfrac{ln(\dfrac{1}{2408})}{1.2\times 10^{-4}}\ years\\\\t=64887.9\ years](https://tex.z-dn.net/?f=kt%3D-ln%28%5Cdfrac%7B%5BA_t%5D%7D%7B%5BA_o%5D%7D%29%5C%5C%5C%5Ct%3D-%5Cdfrac%7Bln%28%5Cdfrac%7B%5BA_t%5D%7D%7B%5BA_o%5D%7D%29%7D%7Bk%7D%5C%5C%5C%5Ct%3D-%5Cdfrac%7Bln%28%5Cdfrac%7B%5BA_o%5D%7D%7B%5BA_o%5D%5Ctimes%202408%7D%29%7D%7B1.2%5Ctimes%2010%5E%7B-4%7D%7D%5C%20years%5C%5C%5C%5Ct%3D-%5Cdfrac%7Bln%28%5Cdfrac%7B1%7D%7B2408%7D%29%7D%7B1.2%5Ctimes%2010%5E%7B-4%7D%7D%5C%20years%5C%5C%5C%5Ct%3D64887.9%5C%20years)
Therefore , the rock is 64887.9 years old .
Hence , this is the required solution .
Answer: 50% Tt, 25% short, 75% tall
Explanation: Tt x Tt —> TT tt Tt tT possible
proportions by genotype TT 25% Tt 50% tt 25%
T dominant so
proportions by phenotype tall (TT, Tt) 75% short (tt) 25%
B.To Understand group behavior through observation
Answer:
DE.......................................
Answer:
An inland location, because land has lower specific heat than water
Explanation:
The specific heat is a measure of how much heat must be supplied to warm up a substance by a certain number of degrees.
Water has a much higher specific heat than land, so it takes much more heat energy to heat up a given mass of water compared to the land.
To say it another way, the specific heat of land is much less than that of water, so it doesn't take as much heat energy to warm up the land.
Thus, an inland location will be relatively warmer during summers.