A jar contains 30 marbles. It has 10 red, 8 black and 12 green marbles. Two marbles are drawn, the first is not returned before
1 answer:
Answer:
P(Both Green) = 22/145
Step-by-step explanation:
The probability of drawing green on the first drawn is P(First Green) = 12/30 = 2/5.
Having drawn green in the first drawn, the probability of drawning green in the second drawn is P(Second Green) = 11/29.
Then, the probability that both marbles are green is obtained by multiplying both probabilities as follows:
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<u>End behavior: </u>
The parent function is: f(x) = x³, which starts (from the left side) at -∞ and ends (on the right side) at +∞.
<u>Zeroes:</u>
f(x) = x³ + 2x² - 8x
0 = x³ + 2x² - 8x
0 = x(x² + 2x - 8)
0 = x(x + 4)(x - 2)
0 = x 0 = x + 4 0 = x - 2
x = 0 x = -4 x = 2
<u>Intervals:</u>
Put the zeroes in order: -4, 0, 2
since f(x) is increasing from the left then the interval from -4 to 0 is positive and the interval from 0 to 2 is negative.
<u>Graph:</u>
see attachment
