A jar contains 30 marbles. It has 10 red, 8 black and 12 green marbles. Two marbles are drawn, the first is not returned before
the second one is drawn. What is the probability that both marbles are green?
P(Both Green) =
4 / 5
P(Both Green) =
11 / 75
P(Both Green) =
28 / 325
P(Both Green) =
22 / 145
1 answer:
Answer:
P(Both Green) = 22/145
Step-by-step explanation:
The probability of drawing green on the first drawn is P(First Green) = 12/30 = 2/5.
Having drawn green in the first drawn, the probability of drawning green in the second drawn is P(Second Green) = 11/29.
Then, the probability that both marbles are green is obtained by multiplying both probabilities as follows: 
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The answer is 22.3 i hope that helped
Answer:
Should be around 4.5
Step-by-step explanation:
If you round 31.53 to the nearest ten dollars, you get 30, 15 percent of 30 is 4.5
ALL LINES CAN BE REPRESENTED IN THE FORM
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So the line is:

Marcus went above his budget as 25% percent of his allowance would be $5, and he went $2.42 over.