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liubo4ka [24]
3 years ago
7

Nitrogen and oxygen are the most abundant gases in Earth’s atmosphere. A nitrogen molecule is 0.00000000003 meters larger than a

n oxygen molecule. Which statements describe writing 0.00000000003 in scientific notation? Check all that apply. The exponent is negative. The exponent is positive. The coefficient is 0.3. The exponent represents the number of places the decimal moves.
Mathematics
2 answers:
goblinko [34]3 years ago
7 0

The correct answers are:

A:The exponent is negative.

D:The exponent represents the number of places the decimal moves.

E:The decimal moves to the right.

(i know this because i had just done this and got it right)

RSB [31]3 years ago
3 1
0.00000000003 \rightarrow 3 \times 10^{-11}



\textrm {Answer:}

\bullet \textrm{The exponent is negative.}

\bullet \textrm{The exponent represents the number of places the decimal moves.}
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Please help me!
marusya05 [52]

Answer:


Step-by-step explanation:

Nice summary problem.

<AEC

  • AEC = 360 - 243.5 = 116.5    
  • The number of degrees in 1 rotation of a circle = 360o. You have accounted for 243.5 degrees. What is left over is the answer.

<EAD and <ECD

Both of these are tangents to a circle. Tangents meet radii at 90 degree angles.

<EAD = <ECD = 90 degrees

<ABC

<ABC is 1/2 the central angle. The Central angle is <AEC

  • < AEC = 116.5
  • <ABC = 1/2 * 116.5
  • <ABC = 58.25

<ADC

There are 2 ways of doing this. You should know both of them.

<em><u>One</u></em>

All quadrilaterals = 360 degrees. You know three of the angles. You should be able to find ADC

  • <ADC + 90 + 90 + 116.5 = 360     Add the four angles together.
  • <ADC + 296.5 = 360                   Combine terms on the left
  • <ADC = 360 - 296.5                    Subtract 238.25 from both sides
  • <ADC = 63.5                                 Answer

<em><u>Method Two</u></em>

<ADC = 1/2 (major Arc - Minor Arc)  This formula is fundamental to circle / tangent properties. The Major arc is the larger of the two parts of the circumference of a circle. The Minor arc is the smaller.

  • <ADC = 1/2(243.5 - 116.5)
  • <ADC = 1/2(127)
  • <ADC = 63.5
8 0
3 years ago
each time kim pour water from a jug into a glass, exactly 10% of the water remaining in the jug is used. What is the minimum num
Gnoma [55]

The <em><u>correct answer</u></em> is:

At least 7 times.

Explanation:

Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.

After two times, we would have 0.9(0.9) = 0.81 = 81% of the water; each time she pours, the number of times 0.9 is multiplied by itself changes.  This makes this an exponential inequality (it is not an equation, as we want "less than half of the water"):

0.5 < 0.9^x

To solve this, we will use logarithms:

\log_{0.9}(0.5)

4 0
3 years ago
HELPP ME<br> s + 3 Five6= 6 17
Oduvanchick [21]

Answer:The crystal structures of five 6-mercaptopurine derivatives, viz. 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(3-meth­oxy­phen­yl)ethan-1-one (1), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-meth­oxy­phen­yl)ethan-1-one (2), C16H14N4O3S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-chloro­phen­yl)ethan-1-one (3), C15H11ClN4O2S, 2-[(9-acetyl-9H-purin-6-yl)sulfan­yl]-1-(4-bromo­phen­yl)ethan-1-one (4), C15H11BrN4O2S, and 1-(3-meth­oxy­phen­yl)-2-[(9H-purin-6-yl)sulfan­yl]ethan-1-one (5), C14H12N4O2S. Compounds (2), (3) and (4) are isomorphous and accordingly their mol­ecular and supra­molecular structures are similar. An analysis of the dihedral angles between the purine and exocyclic phenyl rings show that the mol­ecules of (1) and (5) are essentially planar but that in the case of the three isomorphous compounds (2), (3) and (4), these rings are twisted by a dihedral angle of approximately 38°. With the exception of (1) all mol­ecules are linked by weak C—H⋯O hydrogen bonds in their crystals. There is π–π stacking in all compounds. A Cambridge Structural Database search revealed the existence of 11 deposited compounds containing the 1-phenyl-2-sulfanyl­ethanone scaffold; of these, only eight have a cyclic ring as substituent, the majority of these being heterocycles.

Keywords: crystal structure, mercaptopurines, supra­molecular structure

Go to:

Chemical context  

Purines, purine nucleosides and their analogs, are nitro­gen-containing heterocycles ubiquitous in nature and present in biological systems like man, plants and marine organisms (Legraverend, 2008 ▸). These types of heterocycles take part of the core structure of guanine and adenine in nucleic acids (DNA and RNA) being involved in diverse in vivo catabolic and anabolic metabolic pathways.

6-Mercaptopurine is a water insoluble purine analogue, which attracted attention due to its anti­tumor and immunosuppressive properties. The drug is used, among others, in the treatment of rheumathologic disorders, cancer and prevent

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
6th grade math I reallyyyyy neeedd helpp
UNO [17]
Hello!

Question 6:
To find the area of the pennant, we need to multiply the length by the width. 
12 x 18 = area
12 x 18 = 216
The answer is 216 square inches.

Question 7:
The perimeter of the square is 24cm and the area is 36 square cm.
The perimeter of the rectangle is 30cm and the area is 50 square cm. 
They have different perimeters and different areas.

I hope this helps you! Have a great day!
-Mal

4 0
2 years ago
Simplify 2.4 : 0.88 : 4.8 as ratios
vovangra [49]

Answer:

61:22:120

Step-by-step explanation:

Multiply each by 100

244:88:480

Now simply

122:44:240

61:22:120

(Just check to see or compare with others to see if answer is right)

5 0
2 years ago
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