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3 years ago

Solve the system using substitution.x+y=-2&x-y=-8 (–3, 5) (5, –3) (3, –5) (–5, 3)

Mathematics

1 answer:

AleksAgata [21]3 years ago

7 0

Answer:

(-3, 5)

Step-by-step explanation:

X + y = 2---------------1

X - y = 8----------------2

Substitution method

X = 8 + y

Put x = 8+ y in 1 above

(8+y) +y= 2

2-8= 2y

-6 = 2y

Y= -3

Do same for x

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4 years ago

Solve each system by substitution. Y= -3x + 4 Y= 4x - 10

tatyana61 [14]

Answer:

Step-by-step explanation:

Y= -3x + 4..........(1)

Y= 4x - 10...........(2)

Substituting (1) into (2)

-3x + 4 = 4x - 10

-3x - 4x = -10 - 4

-7x = -14

x = -14/-7

x = 2

Putting x in (2)

y = 4(2) - 10

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4 years ago

Marge and Kimo equally Shared 1/4 of a pie that was left over. What fraction of the original pie did each friend get? Use the pi

luda_lava [24]

Answer:

1/8

Step-by-step explanation:

1/4 divided by 2

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3 years ago

What is 12n^2m^4n/28n^4m^3 simplified?

Serggg [28]

The answer is

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3 years ago

Read 2 more answers

Find the slope-intercept form of the equation of the line that passes through the point (5,1) and is perpendicular to the line 2

Vlad1618 [11]

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

Convert 2x + 5y = 10 to the slope0intercept form:

$2x+5y=10$ subtract 2x from both sides

$5y=-2x+10$ divide both sides by 5

$y=-\dfrac{2}{5}x+2$

Let $k:y=m_1x+b_1$ and $l:y=m_2x+b_2$

$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

We have $m_1=-\dfrac{2}{5}$

Therefore

$m_2=-\dfrac{-\frac{2}{5}}=\dfac{5}{2}$

We have the equation of a line:

$y=\dfrac{5}{2}x+b$

Put the coordinates of the point (5, 1) to the equation of a line:

$1=\dfrac{5}{2}(5)+b$

$1=\dfrac{25}{2}+b$ subtract $\dfrac{25}{2}$ from both sides

$-\dfrac{23}{2}=b\to b=\dfrac{23}{2}$

Answer: $\boxed{y=\dfrac{5}{2}x+\dfrac{23}{2}}$

4 0

3 years ago