3.Slope: 10 Y int: 5
4. Slope: 5 Y int: 10
6.Slope: 1/3 Y int: 3.5
7.Slope: 4/3 Y int: -1
8.Slope: 2/-4 Y int: -1
The way you do this is the Y int is where the line crosses through the y-axis. Finding the slope is finding the rise over run (y/x). It's easy to find when you know how to.
Use 4. as an example. Start where at (-3,-5) or (-2,0). Each 'rise' up 5 and 'runs' one block over, giving you the slope of 5/1 or 5 simplified.
7 is harder, but start at (-3,-5). It 'rises' up 4, then 'runs' 3, also giving you the y int, as it crosses the axis. As the rise is 4 and run is 3, it creates the slope 4/3.
C is correct. You have to pay attention to the corresponding sequences of the vertices. C is correct because in the three triangles, MON, MPO, OPN are the right angles, respectively. However, the angles are not consistent in other given choices.
Answer:
your question is really not clear but if you were to put the -4 in the Y then the answer would be X=1/3, if you plug in -4 for X and find Y then Y = -17
Step-by-step explanation:
plug in -4 in Y
-4=3x-5 add 5 on both sides,
1 = 3x divide 3 on both sides
1/3= x
plug in -4 in X
y = 3(-4)-5 multiply 3 and -4 = -12
y = -12-5 subtract the -12 and -5 = -17
y = -17
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
