Use this property of logarithms:

Your equation transforms into:

Now, you have to apply the definition of a logarithm to express the equation in exponential form:

In case you don't remember, this is the definition of a logarithm:

The log is the exponent (y) you have to raise the base (b) to in order to get the power (x).
Finally, solve the rational equation:



The correct answer is d.
<span>two hundred ninety one divided by two = 291/2 = 145.5
</span>
Here is you're answer:
In order to cross multiply you have to multiply the numerator and denominator of the first fraction by the bottom number of the second fraction and see if the equation is still true:
Therefore you're answer is "3 × 1 = 5 × 10."
Hope this helps!
Answer:
i think the 2nd one is correct .. i have not fluent in english to explain the answer.
Answer:
<h3>y + 2 = 3/7(x-7)</h3>
Step-by-step explanation:
The point-slope form of the equation will be expressed as;
y - y0 = m(x-x0) where;
m is the slope
(x0, y0) is the point on the line
Given
Slope m = 3/7
Point (x0, y0) = (7, -2)
Substitute into the equation;
y - y0 = m(x-x0)
y - (-2) = 3/7 (x - 7)
<em>y + 2 = 3/7(x-7)</em>
<em>Hence the equation in point-slope form is y + 2 = 3/7(x-7)</em>