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3 years ago

12

4 Calvin is a train company manager.

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

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At a restaurant you only have 20 dollars to spend on dinner. in addition to the cost of the meal you must pay only 5% sales tax

aev [14]

Alright so to do this you need some basic algebra
you have to pay an extra 20% of whatever you buy
thus we can make the following equation
.2x+x=20 (since 20 is the amount of money you have)
combining the like terms,
1.2x=20
and finally, dividing both sides by 1.2
x=$16.67
don't forget to check!
.05*16.67=.83 (sales tax makes the total $17.5)
.15*16.67=2.5 (tip makes the total $20)
whaddya you know, it works!
most expensive item you can buy will cost $16.67
hope this helped!

4 0

3 years ago

The angle between two vectors ⃗ = 2⃗ − ⃗ and ⃗⃗ = ⃗ − 3⃗ is

ella [17]

Answer:

please post the picture of this question

thank you

3 0

3 years ago

Solve the right triangle. Round to the nearest degree and nearest tenth of a unit. What is the right angleV?

N76 [4]

Answer:

m∠V ≈ 61°

Step-by-step explanation:

The hypotenuse and the side opposite the angle of interest are given. The relevant trig relation is ...

Sin = Opposite/Hypotenuse

sin(V) = XW/XV = 7/8

The inverse sine function is used to find the angle:

V = arcsin(7/8) ≈ 61°

4 0

2 years ago

How do you write 6,007,200 in two other forms

miskamm [114]

Six million and seventy two hundred. 6.0072 x 10*

*=6

3 0

4 years ago

In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t

Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

$(Y_1)^2 and (Y_2)^2$ have $x^2$ distribution with 1 degree of freedom

and $V=(Y_1^2)+(Y_2)^2$ has x^2 with 2 degree of freedom

$F_v(v)=\frac{e^{-\frac{v}{2}}}2$

Since we have to find the density formula

$U=\sqrt{V}$

We use method of transformation

$h(V)=\sqrt{U}\\\\=U$

There inverse function is $h^-^1(U)=U^2$

We derivate the fuction above with respect to u

$\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u$

Therefore,

$F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U$

8 0

3 years ago