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3 years ago

1.) Name the following compound: (image 1)

Chemistry

2 answers:

OLEGan [10]3 years ago

6 0

Answer :

(1) The correct option is, 2-ethylpentane

(2) The correct option is, 2,3-dimethylpentane

(3) The correct option is, 2-methyl-2-butene

(4) The correct option is, 7-ethyl-4-dodyne

(5) The correct option is, pentanoic acid

Explanation :

The basic rules for the naming of organic compounds are :

First select the longest possible carbon chain.

The longest possible carbon chain should include the carbons of double or triple bonds.

The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and carboxylic acid by adding the suffix -oic acid.

The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.

The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.

If two or more similar alkyl groups are present in a compound, the words di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.

rewona [7]3 years ago

5 0

1.) 3-methylhexane
2.) 2,3-dimethylpentane
3.) 2-methyl-2-butane
4.) 7-ethyl-4-dodyne
5.) pentatonic acid
Just took this these are the right answers

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Sloan [31]

Answer:

Mass = 42.8g

Explanation:

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Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.

Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

Ammonia = 63.4g × 1mol / 17.031 g = 3.7226mol

Oxygen = 63.4g × 1mol / 32g = 1.9813mol

Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.

If all of the 1.9831 moles of oxygen were to be used up, there would need to be 1.9831 × 4 / 5 or 1.5865 moles of Ammonia. We have 3.72226 moles of ammonia - Far excess. Because there is an excess of Ammonia, the Oxygen amount is used to calculate the amount of the products in the reaction.

Step 4: Use the amount of limiting reactant to calculate the amount of H2O produced.

5 moles of O2 = 6 moles of H2O

1.9831 moles = x

x = (1.9831 * 6 ) / 5

x = 2.37972 moles

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4 years ago

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Answer:

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Explanation:

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