Describe the physical properties that can be used to classify and compare matter.
1 answer:
You might be interested in
Answer: The correct answer is C.
Explanation: Frictional force is the contact force which resists the motion of one surface on another.
Mathematically,
where,
f = frictional force
= Coefficient of friction
N = normal force acting on a body
We need to find the ratio of force of sliding friction ( which is a type of frictional force) and the normal force acting on an object. This will be equal to coefficient of friction.
Hello!
We have the following data:
v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15
P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K
<span>We apply the data above to the Clapeyron equation (gas equation), let's see:
</span>
I hope this helps. =)
We have the following data:
v (volume) = ? (in L)
n (number of mols) = 1,5 mol
T (temperature) = 22 ºC
First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15
P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K
<span>We apply the data above to the Clapeyron equation (gas equation), let's see:
</span>
I hope this helps. =)