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Elena-2011 [213]
4 years ago
7

The volume of a gas is 400.0 ml when the pressure is 1.00 atm. at the same temperature, what is the pressure at which the volume

of the gas is 2.0 l?
a. 0.5 atm
b. 5.0 atm
c. 0.20atm
d. 800 atm
Chemistry
2 answers:
almond37 [142]4 years ago
4 0
C. 0.20atm (hope this is correct)
jarptica [38.1K]4 years ago
3 0
The question mentions a change in volume from 400 mL to 2L, which is accompanied by a change in pressure from 1 atm. Therefore, the premise of this question is Boyle's Law, which notes that pressure is inversely proportional to volume at constant temperature (as volume increases, pressure decreases, and vice versa). As such, Boyle's Equation can be used to determine the final pressure of the air. 

Boyle's Equation:      P₁V₁    =    P₂V₂
Since the initial volume (V₁) is 400 mL =  0.4 L, the final volume (V₂) is 2L and the initial pressure is 1 atm, then we can substitute these into the equation to find the initial volume (V₁).

                                                  P₁V₁    =    P₂V₂
∴ by substituting the known values,                               
                     ⇒     (1 atm) (0.4 L)  =  (P₂)(2 L)                                                              
                     ⇒                       P₂  =  (0.4 atm L) ÷ ( 2 L)                                     
                     ⇒                       P₂  =  0.2 atm

Thus the answer is 0.20 atm (option C)
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Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

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