Answer:
Explanation:
Graham's law of diffusion states that the rate at which effusion occurs in two gases is equal to the square inverse of each of their molar masses.
In a series circuit, the current through each of the components is the same, and the voltage across the circuit is the sum of the voltages across each component. In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through each component.
Filtration separates mixture which is not dissolved and also they need to have different size of particles. Distillation usually separates mixture which will be dissolved but has different boiling point.
Answer:
145.78g/mol
Explanation:
Let the time taken for the two gas to effuse be x
For O2:
Volume = 6.51mL
Time = x
Rate (R1) = volume/time
R1 = 6.51/x
For the unknown gas:
Volume = 3.05mL
Time = x
Rate (R2) = Volume/time
R2 = 3.05/x
Now, we can obtain the molar mass of the unknown gas as follows:
R1 = 6.51/x
M1 (O2) = 16 x 2 = 32g/mol
R2 = 3.05/x
M2(unknown gas)
R1/R2 = √(M2/M1)
(6.51/x)/(3.05/x) = √(M2/32)
6.51/3.05 = √(M2/32)
Take the square of both side
(6.51/3.05)^2 = M2/32
Cross multiply to express in linear form:
M2 = (6.51/3.05)^2 x 32
M2 = 145.78
Therefore, the molar mass of the unknown gas is 145.78g/mol