<span>decomposition of SrCO3 to SrO and CO2 =change in mass
moles of CO2 =(1.850 g - 1.445 g).
</span>Mass of <span>C<span>O2</span></span><span> in mixture: 1.850-1.445 = 0.405g
</span>0.405g/44.01 g/mol <span>C<span>O2</span></span><span> = 0.0092 moles </span><span>C<span>O2</span></span><span>.
</span>ratio of <span>C<span>O2</span></span><span> to SrO in Sr</span><span>C<span>O3</span></span><span> is 1:1
</span><span> mass ratio = 1.358/1.850 = 0.7341, </span>
or 73.41% Sr<span>C<span>O3</span></span><span>.
</span>hope this helps
From the information we have, this block of brown sugar has a volume of 8cm3
The mass of the block is 12. 9 grams.
We need to find out the density of the sugar.
For a solid material the formula for calculating density is given as:
Density = mass / volume
Therefore we simply fit in the above given values into this formula, so:
Density = 12.9 / 8
Density = 1.61
Therefore the density of the block of sugar is 1.61g/ml