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Ahat [919]
3 years ago
11

sam needs 4/6 cup of laundry detergent for his laundry. The cap on top of the laundry detergent holds 1/3 cup. He has 1 capful o

f detergent. Does he have enough explain.
Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0
Simply 4/6 to its equivalent fraction of 2/3
Is 1/3 of a cup enough for the 2/3 a cup needed? No. So he doesn't have enough
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Using the midpoint method (show your work), calculate the price elasticity of demand when the price of a barrel of gosum berries
Setler79 [48]

Answer:

0.18

Step-by-step explanation:

Given that:

P₁ = $10, P₂ = $20

From the tables Q₁ = 900, Q₂ = 800

Using midpoint method:

Percentage change in quantity = \frac{Q_2-Q_1}{(Q_1+Q_2)/2} *100\%=\frac{800-900}{(900+800)/2}*100\%= -11.76\%\\

Percentage change in price =

\frac{P_2-P_1}{(P_1+P_2)/2} *100\%=\frac{20-10}{(20+10)/2}*100\%= 66.67\%\\

Price of elastic demand = Percentage change in quantity/ Percentage change in price = -11.76% / 66.67% = 0.18

The Price of elastic demand is positive because we took the absolute value and elasticity are always positive

Therefore since Price of elastic demand < 1, the demand is inelastic in this interval.

This means that, along the demand curve between $10 to $20, if the price changes by 1%, the quantity demanded will change by 0.18%. A change in the price will result in a smaller percentage change in the quantity demanded. For example, a 10% increase in the price will result in only a 1.8% decrease in quantity demanded and a 10% decrease in the price will result in only a 1.8% increase in the quantity demanded

7 0
3 years ago
Please help me now I need help
Fudgin [204]

Answer: B

Step-by-step explanation:

4 0
3 years ago
Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with
worty [1.4K]

Answer:

z

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean \mu =26 kilograms and standard deviation \sigma=4.2 kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

X"

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(26,4.2)  

Where \mu=26 and \sigma=4.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

z=\frac{42.6-26}{4.2}=3.95

So then the corresponding z scale would be:

z

7 0
2 years ago
What is the opposite of real number
Dafna1 [17]

An <em>imaginary number</em>. The defining property of an imaginary number is that has the number i attached to it, where i² = -1.

A few examples of imaginary numbers: 3i, i, -7i, (√3)i, (1/2)i

7 0
3 years ago
Read 2 more answers
A boat traveled 128 kilometers in
AlekseyPX

Answer:

The Distance cover by boat in 2 hours and 15 minutes is 72 km  

Step-by-step explanation:

Given as :

The Distance cover by boat = 128 kilometer

The time taken is 4 hours

As , Distance = Speed ×Time

So , Speed = \frac{Diastance}{Time}

Or, Speed = \frac{128 km}{4 hours}

∴   Speed = 32 km per hour

Now, again The boat travel 2 hours and 15 minutes further with speed 32 kmph

So, Time2 = 2 + \frac{15}{60}

Or,  Time2 = 2 + \frac{1}{4}

I.e Time2 = \frac{9}{4}  hours

Again , Distance = Speed ×Time

So ,    Distance = 32kmph × \frac{9}{4}  hours

I.e       Distance  = (\frac{32\times 9}{4}) = 72 kilometer

Hence The Distance cover by boat in 2 hours and 15 minutes is 72 km  Answer

5 0
2 years ago
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