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AfilCa [17]
2 years ago
8

Avani has 5 posters she wants to hang on the wall. How many different ways can the posters be arranged in a row?​

Mathematics
2 answers:
Whitepunk [10]2 years ago
8 0

Answer:

15 ways

Step-by-step explanation:

The first can be in 5 spots

The second can be in 4 spots.

The third can be in 3 spots.

The fourth can be in 2 spots.

The fifth can be in 1 spot.

The sum of all of the numbers is 15.

5 + 4 + 3 + 2 + 1 = 15

IceJOKER [234]2 years ago
4 0
<h3>Given ↓</h3>
  • Avani has 5 posters
<h3 /><h3>To Find ↓</h3>
  • The number of ways Avani can arrange her 5 posters

<h3>Calculations ↓</h3>

First, how many ways are there for the 1st poster?

It can be the first, the 2nd, the 3rd, the 4th, or the 5th.

How many ways are there for the 2nd poster?

there are 4 ways, because one of them is occupied by the first poster

There are 3 ways for the 3rd poster, 2 ways for the 4th poster and 1 way for the 5th poster.

Multiply the number of ways together : 120 ways

These are the ways we can arrange the 5 posters ↓

\boxed{\\\begin{minipage}{2 cm}poster~1 \\ \\ \end{minipage}}     \boxed{\\\begin{minipage}{2cm}poster~2 \\ \\ \end{minipage}}   \boxed{\\\begin{minipage}{2cm}poster~3 \\ \\ \end{minipage}}  \boxed{\\\begin{minipage}{2cm}poster~4 \\ \\ \end{minipage}}  \boxed{\\\begin{minipage}{2cm}poster~5 \\ \\ \end{minipage}}

We could replace P1 (Poster 1) with any of the 4 posters here, and do the same thing with the other posters...

Overall, believe it or not, there are 120 ways to arrange these 5 posters.

A quick way to calculate this is

5!=5*4*3*2*1

120

<h3>Number of ways ↓</h3>

120

hope helpful ~

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Answer:

\begin{cases}y=-5x+1\\y=5x-4 \end{cases}

Step-by-step explanation:

Slope-intercept form of a <u>linear equation</u>:

\boxed{y=mx+b}

where:

  • m is the slope.
  • b is the y-intercept (where the line crosses the y-axis).

<u>Slope formula</u>

\boxed{\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}}

<u>Equation 1</u>

<u />

Define two points on the line:

  • \textsf{Let }(x_1,y_1)=(-1, 6)
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<u>Substitute</u> the defined points into the slope formula:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1-6}{0-(-1)}=-5

From inspection of the graph, the line crosses the y-axis at y = 1 and so the y-intercept is 1.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

y=-5x+1

<u>Equation 2</u>

<u />

Define two points on the line:

  • \textsf{Let }(x_1,y_1)=(1, 1)
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<u>Substitute</u> the defined points into the slope formula:

\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-4-1}{0-1}=5

From inspection of the graph, the line crosses the y-axis at y = -4 and so the y-intercept is -4.

Substitute the found slope and y-intercept into the slope-intercept formula to create an equation for the line:

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