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3 years ago

Find the limit as x approaches 0 for cos(2x) / x

1 answer:

5 0

We are asked to determine the limits of the function cos(2x) / x as x approaches to zero. In this case, we first substitute zero to x resulting to 1/0. A number, any number divided by zero is always equal to infinity, Hence there are no limits to this function.

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Can somebody help me with 20. Thank you!!!

riadik2000 [5.3K]

Answer:

What do you mean, I'll help.

Step-by-step explanation:

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2 years ago

△PQR has two known interior angles of 34°, and 80°. △RST has two known interior angles of 24°, and 90°. What can be determined a

Nonamiya [84]

B.the triangles are not similar

7 0

3 years ago

Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this problem, we have that:

$f(x) = x^{2} + 3x - 1$

$a = 1, b = 3, c = -1$

$\bigtriangleup = 3^{2} - 4*1*(-1) = 13$

$x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3$

$x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3$

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0

3 years ago

PLEASE HELP ME!!!!!!!!

hjlf

The Answer Is 60
2.5 x 8 The Number Of Sides On That Shape Was 8
2.5 x 8 = 20
20 times the radius 3
20 x 3 = 60
60cm^2

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4 0

2 years ago

Read 2 more answers

Solve 4(x + 1) = 4x + 4 A- No solution B- 0 C- All real numbers D- 1

Tcecarenko [31]

The answer is: c- all real numbers

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2 years ago