The x-intercept of a graph is the point where the graph crosses the x-axis
<h3>(a) Graph</h3>
The function is given as:

See attachment for the graph of the function.
From the attachment, the approximated x-intercepts are -7 and -1
<h3>(b) Type of solution</h3>
From the attached graph, we can see that the curve crosses the x-axis at non-terminating decimals
Hence, the solutions of the equation are irrational.
<h3>(c) The vertex</h3>
This is the minimum or the maximum point of a parabola.
From the attached graph, the minimum point is at (-4,-7)
Hence, the coordinates of the vertex of the parabola is (-4,-7), and it is exact (not approximated)
Read more about parabolas at:
brainly.com/question/4061870
D. 6
I hope this helps you out! :D
Answer:
x = -7
Step-by-step explanation:
The vertex form of this equation tells us it is a downward-opening parabola with its vertex at (-7, -3). The line of symmetry is the vertical line through the vertex: x = -7.
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Vertex form is ...
y = a(x -h) +k
where a is the vertical expansion factor, and (h, k) is the vertex. When a < 0, the parabola opens downward. When a > 0, it opens upward. (When a=0, the "parabola" is a horizontal line at y=k.)
Answer: 
Step-by-step explanation:
Given
The area is bounded by
and x-axis from [0,2]
The volume generated for
when rotated about the x-axis in the interval [a,b] is

Insert the values
![\Rightarrow V=\int_0^2\pi x^4dx\\\\\Rightarrow V=\pi \int_0^2x^4dx\\\\\Rightarrow V=\pi \left[ \dfrac{x^5}{5}\right]_0^2\\\\\Rightarrow V=\dfrac{2^5\pi }{5}\\\\\Rightarrow V=\dfrac{32\pi }{5}\ \text{unit}^3](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D%5Cint_0%5E2%5Cpi%20x%5E4dx%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cpi%20%5Cint_0%5E2x%5E4dx%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cpi%20%5Cleft%5B%20%5Cdfrac%7Bx%5E5%7D%7B5%7D%5Cright%5D_0%5E2%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B2%5E5%5Cpi%20%7D%7B5%7D%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B32%5Cpi%20%7D%7B5%7D%5C%20%5Ctext%7Bunit%7D%5E3)