Answer:
-3.392
Step-by-step explanation:
2.34
1.052
+_____
= 3.392
Answer/Step-by-step explanation:
Part A: Net A is the correct net. If we decide to fold the net, we'd get the shape of the prism. Folding back net B won't give us the shape of the prism because of the position and arrangement of the right triangular bases.
Part B:
AB = 3in
BC = 5 in
CD = 9.4 in
Part C: surface area of the prism can be calculated by calculating the area of each part of the net, and summing them together as follows,
Area of the 2 triangular bases = 2(½*base*height of triangle) = 2(½*4*3) = 2*2*3 = 12 in²
Area of the three rectangles =
![= (9.4*4) + (9.4*3) + (9.4*5) = 37.6 + 28.2 + 47 = 112.8 in^2](https://tex.z-dn.net/?f=%3D%20%289.4%2A4%29%20%2B%20%289.4%2A3%29%20%2B%20%289.4%2A5%29%20%3D%2037.6%20%2B%2028.2%20%2B%2047%20%3D%20112.8%20in%5E2)
Surface area of prism = 12 + 112.8 = 124.8 in²
The answer is 21. 75²=5625 72²=5184 5625-5184=441 √441=21 so 21 is your answer. I hope this helps. The formula to figure out the hypotenuse A²+B²=C² can also be used to find a leg. Since we have one leg and the hypotenuse I was able to figure this out.
Part A
(3x)^2*x^4
(3x)*(3x)*x^4 .... expand out (3x)^2
(3*3)*(x*x*x^4)
9x^6
Answer: 9x^6
============================================
Part B
It appears that Tonya forgot to square the 3 term and had this as her steps
(3x)^2*x^4
3x^2*x^4
3x^(2*4)
3x^8
Which is incorrect as the answer in part A indicates.
Not only is the '3' part wrong, but also the exponent of 8. Instead of multiplying the exponents, she should have added them.
The rule is a^b*a^c = a^(b+c). In this case, a = x, b = 2 and c = 4.
So x^2*x^4 = x^(2+4) = x^6