A1 = 3 and an = an − 1 − 3
a1 = 2 and an = an − 1 + 0.5
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First you solve the inequality. Add the variables that can be added together. That would be -3 + 1=2. Now the equation is 2 + x<6. After you change the 2 into a negative and put it under the 6 and subtract. that is 3. 3 is the number you put on the number line. When you fine and plot three you make a dot above it. You fill in the dot since the less then sign has a line beneath it. Then you draw a line from the dot to the end of the number line from the direction the sign is facing. It’s a less then sign, so you would draw the line to the left.
Answer:
4 cups
Step-by-step explanation:
in order to convert 32 ounces into cups, you must divide 32 by 8. this will give you 4, your answer.
If this helps, please mark me brainliest. :)
For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.
[a] 50%
![\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed}}{\text{Period 2's class}} =\frac{12}{24} =0.5,\:0.5*100=50\%](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Ctext%7Bwanted%20outcomes%7D%7D%7B%5Ctext%7Bpossible%20outcomes%7D%7D%20%3D%5Cfrac%7B%5Ctext%7Bstudent%20failed%7D%7D%7B%5Ctext%7BPeriod%202%27s%20class%7D%7D%20%3D%5Cfrac%7B12%7D%7B24%7D%20%3D0.5%2C%5C%3A0.5%2A100%3D50%5C%25)
[b] 52%
![\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed from Period 3}}{\text{fails from both classes}} =\frac{13}{25} =0.52,](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Ctext%7Bwanted%20outcomes%7D%7D%7B%5Ctext%7Bpossible%20outcomes%7D%7D%20%3D%5Cfrac%7B%5Ctext%7Bstudent%20failed%20from%20Period%203%7D%7D%7B%5Ctext%7Bfails%20from%20both%20classes%7D%7D%20%3D%5Cfrac%7B13%7D%7B25%7D%20%3D0.52%2C)
![\displaystyle 0.52*100=52\%](https://tex.z-dn.net/?f=%5Cdisplaystyle%200.52%2A100%3D52%5C%25)