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Anna71 [15]
3 years ago
12

Sarah makes $10 an hour babysitting and $5 an hour gardening. her goal is to make $80 a week while working 12 hours. how many ho

urs will Sarah have to work at each job to accomplish her goal
Mathematics
1 answer:
vekshin13 years ago
4 0
Call b the amount of babysitting hours and 5 the amount of gardening hours.

10b+5g=80
b+g=12

Subtract 5 times the second equation from the first to get:

5b=20
Thus, b=4.  g=12-4, or 8.  Therefore, Sarah spends 4 hours babysitting and the rest gardening.
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X^3 + 4x^2 + 5x +20 factor by grouping
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Step-by-step explanation:

x³ + 4x² + 5x + 20

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Andrea is told that the means of two groups in a study were statistically significant. She knows the means and standard deviatio
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Answer:

Cohen's D

Step-by-step explanation:

Cohen's D is a statistic that measures effect size. It shows standardised difference between 2 means.

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This is the most appropriate method in the given scenario

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3 years ago
A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
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Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

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