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Otrada [13]
3 years ago
10

How do you write the point slope form of a linear equation?

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
Y-y=m(x-x). That is the formula for point slope form. You want to take the two y axis and subtract them from each other and m is your slope. Then u take the x axis put them in parentheses and then you u solve with pemdas from the there.
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Hello can somedy help me please <br> thank you in advance
alina1380 [7]

Answer:

Area of the circle=πr²

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Solve 1/p+1/s=1 for p
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Step-by-step explanation:

Multiply through by the L. C. M which is PS.

1/p*ps+1/s*ps=1*ps

P+p=ps

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Find the distance between (-18, 9) and (22,0).
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Step-by-step explanation:

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6 0
3 years ago
At a Psychology final exam, the scores are normally distributed with a mean 73 points and a standard deviation of 10.6 points. T
USPshnik [31]

Answer:

The score that separates the lower 5% of the class from the rest of the class is 55.6.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 73, \sigma = 10.6

Find the score that separates the lower 5% of the class from the rest of the class.

This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 73}{10.6}

X - 73 = -1.645*10.6

X = 55.6

The score that separates the lower 5% of the class from the rest of the class is 55.6.

3 0
3 years ago
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