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3 years ago

How to simply this expression

Mathematics

1 answer:

strojnjashka [21]3 years ago

3 0

Hope this answer your question :)

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Need help with this

olganol [36]

Put a small dot on positive 4 and go down to -3 and out a big dot there and that’s your first coordinate

3 0

3 years ago

3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls

tatuchka [14]

Answer:

$x=\frac{13}{2}, y=\frac{51}{4}$

Step-by-step explanation:

$We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}$

$Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}$

4 0

3 years ago

Not sure! help! please

sergejj [24]

$\dfrac{ \frac{x}{4} + \frac{1}{8} }{ \frac{x^2}{4} } =

\vspace{3mm}

= \dfrac{ \frac{2x}{8} + \frac{1}{8} }{\frac{x^2}{4}} 

\vspace{3mm}

= \dfrac{ \frac{2x+1}{8} }{\frac{x^2}{4}} 

\vspace{3mm}

= \dfrac{2x + 1}{8} \times \dfrac{4}{x^2}

\vspace{3mm}

= \dfrac{2x + 1}{2x^2}$

7 0

3 years ago

HELP ME FIND SLOPE RATE CHANGE WILL GIVE BRAINLIEST

il63 [147K]

Answer:

1. RS= slope of 5/2

2. Pt= slope of -6/1 or -6

3.PQ= slope of 1/5

4. TS=slope of 0

5. QR= slope of -1/2

Step-by-step explanation:

Rise / run then simplify

5 0

3 years ago

Which point is not on the graph of the function y = 3 x ? (0, 0) (5, 15) (9, 3) (7, 21)

Anna11 [10]

Answer:

(9,3)

Step-by-step explanation:

5 0

3 years ago