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alexdok [17]
3 years ago
5

*15 points

Mathematics
1 answer:
LenKa [72]3 years ago
6 0

4 because 4 times 4 is 16

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Find the quotient and any excluded values.<br><br> (x + 5/x^2 + 9x + 20)/(x^2-16/x-4)
Wittaler [7]
By  <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:

         x+5
 ----------------------
   x^2 + 9x + 20

and by 

</span><span>(x^2-16/x-4)
                                       x^2-16
you apparently meant ---------------
                                         x - 4

Please use additional parentheses for clarity.

Dividing,

</span>         x+5                   (x-4)(x+4)
 ----------------------  *  ---------------
   x^2 + 9x + 20                  x-4

Now, x^2 + 9x + 20 factors into   (x+4)(x+5), so what we have now is

       (x+5)(x+4)
------------------------- = 1           This is true for all x, so there are no exclusions.
    (x+4)(x+5)
3 0
3 years ago
How would adding a score of zero to this data affect the mean and medium game scores
Diano4ka-milaya [45]

It wouldn't affect the mean or the median.

8 0
3 years ago
Help me please I have no clue
emmainna [20.7K]

Answer:

x = 12.8

Step-by-step explanation:

i use this calculator to find triangle measurements as long as you know like three values it works

https://www.calculator.net/triangle-calculator.html?vc=90&vx=&vy=10&va=38&vz=&vb=&angleunits=d&x=79&y=19

ik sending a link is hecka sus but you can just look up triangle calculator and it'll pop up

7 0
3 years ago
What is the value of x?
alexandr402 [8]
What is the equation?
8 0
3 years ago
What goes where. JdhshshHshxjancixd
valentina_108 [34]

Answer:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

Step-by-step explanation:

We need to simplify

y +  \frac{2}{5}y

We collect LCM to get;

\frac{5y + 2y}{5}  =  \frac{7y}{5}

Therefore:

\boxed { \frac{7}{5}y } \to \: \boxed {y+ \frac{2}{5}y }

Also we need to simplify:

y -  \frac{2}{5}y

We collect LCM to get;

y -  \frac{2}{5}y =  \frac{5y - 2y}{5}  =  \frac{3}{5} y

Therefore

\boxed { \frac{3}{5}y } \to \: \boxed {y -  \frac{2}{5}y }

5 0
4 years ago
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