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Tcecarenko [31]
3 years ago
9

What is the value of x? enter your answer in the box ___units

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

The value of X is 4 - APEX you’re welcome (:

You might be interested in
What is 2x-4. I really don’t understand
ddd [48]

Answer:

2 * -4 = -8

Step-by-step explanation:

2 * -4 = -8

It is just like multiplying two numbers like... 2 * 4 = 8

You must need to know that:

+a * -b = -c

-a * -b = +c

+a * +b = +c

In your question;

+a * -b = -c

a = 2

b = -4

c = -8

therefore:

2 * -4 = -8

3 0
3 years ago
A submarine sits at -300 meters in relation to sea level. Then it descends 115 meters. What is its new position in
Leokris [45]

Answer:

In this question ;

key word is <em><u>descends</u></em> which means <em><u>going down</u></em>

now the position is -300 which means it's under water and it descends 115 m that means now it's even more under water

position now is -300 -115 = <u>-415m</u>

<u> </u>

3 0
3 years ago
Read 2 more answers
Fill in the blank 1.05 assignment
Neko [114]

Answer -4x

Step-by-step explanation:

distribute the x to 5x and -4

8 0
3 years ago
Read 2 more answers
G(x)=-4x² - 3 find g(-3)​
dimulka [17.4K]

Answer:

-39

Step-by-step explanation:

just plug -3 into x

-4(-3)^2-3=-4*9-3=-36-3=-39

so, g(-3)=-39

hope this helped

4 0
2 years ago
Find a co-terminal angle between 0 and 360 degrees and q=19p/4
arsen [322]

The co-terminal angle between 0 and 360º with \frac{19\pi}{4} is of 135º.

<h3>How to find the co-terminal angle of an angle greater than 360º?</h3>

To find the co-terminal angle of an angle greater than 360º, we have to find the remainder of the division of the angle by 360º.

An angle of pi radians is equivalent to 180º, this angle is of 4.75pi radians, hence the measure in degrees of the angle is of:

4.75 x 180º = 855º.

The remainder of the division of 855º by 360º is of 135º, hence the co-terminal angle between 0 and 360º with \frac{19\pi}{4} is of 135º.

More can be learned about co-terminal angles at brainly.com/question/21384986

#SPJ1

3 0
1 year ago
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