If m1 and m2 are the slopes of each line, for them to be perpendicular you gotta solve
m1 * m2 = -1
9514 1404 393
Answer:
(a, b, c) = (-0.425595, 11.7321, 2.16667)
f(x) = -0.425595x² +11.7321x +2.16667
f(1) ≈ 13.5
Step-by-step explanation:
A suitable tool makes short work of this. Most spreadsheets and graphing calculators will do quadratic regression. All you have to do is enter the data and make use of the appropriate built-in functions.
Desmos will do least-squares fitting of almost any function you want to use as a model. It tells you ...
a = -0.425595
b = 11.7321
c = 2.16667
so
f(x) = -0.425595x² +11.7321x +2.16667
and f(1) ≈ 13.5
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<em>Additional comment</em>
Note that a quadratic function doesn't model the data very well if you're trying to extrapolate to times outside the original domain.
At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless?
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
6 = 2(x + 8) - 5x
6 = 2x + 16 - 5x
6 = 16 - 3x
3x = 16 - 6 = 10
x = 10/3