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givi [52]
4 years ago
12

I look at a random time of day at a digital clock that shows times from 1:00 through 12:59. if i ignore the colon, what is the p

robability that the digits display a palindrome such as 8:08? express your answer as a common fraction.
Mathematics
2 answers:
AnnyKZ [126]4 years ago
8 0

Answer:

19/240

Step-by-step explanation:

First, we compute the total number of possible times that can show. There are 12 possible hours, and 60 possible minutes, so the total number of possible times is 12 * 60 = 720.

Now we compute the number of palindromes. There are 6 palindromes per hour for the nine hours 1 through 9 (1:01, 1:11, 1:21, 1:31, 1:41, 1:51 for example). There is one palindrome per hour from 10 through 12, namely 10:01, 11:11, and 12:21. Hence, the number of palindromes is 6 * 9 + 3 = 57.

Therefore, the probability that the time is a palindrome is 57/720 = 19/240.

Sergio039 [100]4 years ago
5 0

The probability that the digits display a palindrome = 19/240 Ans.

As we know the total no. of possible hours = 12

Total number of possible minutes= 60

Therefore, total no. of possible times that can be shown are = 12

Since total no. of Palindromes possible per hour for the nine hours 1 through 9 = 6

No. of palindromes per hour from 10 through 12 = 1

Therefore, total no of palindromes = (6*9) + 3 = 57

Probability that the digits display a palindrome = 57/720 = 19/240

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3 years ago
Which expression is equivalent to 2(7b + 5)?
DENIUS [597]

2(7b + 5) will equal to 14b+10

Explanation:

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4 0
3 years ago
the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room​
Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

C.S.A.=2h(l+b)

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

C.S.A.=\text{Perimeter of the base} \times h

Putting the given values, we get

C.S.A.=18\times 3

C.S.A.=54

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7 0
3 years ago
1/3 (6x +12) - 2(x-7)=19
Morgarella [4.7K]

Answer:

no solution

Step-by-step explanation:

Given

\frac{1}{3}(6x + 12) - 2(x - 7) = 19 ← distribute parenthesis on left side

2x + 4 - 2x + 14 = 19 , that is

18 = 19 ← not possible

This indicates the equation has no solution

4 0
3 years ago
The length of a rectangle is 5 inches longer than it is wide. If the area is 150 square inches, what are the dimensions of the r
ikadub [295]

Answer:

Width: 10 inches

Length: 15 inches

Step-by-step explanation:

Let the width be w.

Since the length is 5 inches longer than its width, the length = w +5.

Area of rectangle = length x width

w (w +5) = 150

w^2 + 5w = 150

w^2 + 5w -150 = 0

Using quadratic formula,

w = 10 or -15

Since the width cannot be negative,

the width is 10 inches.

Now just substitute w=10 into length = w +5.

length = 10 + 5

= 15 inches

5 0
3 years ago
Read 2 more answers
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