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gizmo_the_mogwai [7]
3 years ago
11

Larry is thinking of a number that is between 0 and 300. What is the correct model for this situation?

Mathematics
2 answers:
Aleksandr [31]3 years ago
6 0

Answer:

 none are correct

Step-by-step explanation:

dsp733 years ago
3 0
The first option is correct
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seraphim [82]

Answer:

its scientific notification is 5×10^9

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The volume of a sphere is 2,240 yd^3. What will be the new volume in the dimensions are multiplied by 1/4?
Veseljchak [2.6K]

Answer:

34.98yd^3

Step-by-step explanation:

Volume of a sphere V=4/3πr3

Where V = 2240yd^3

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2240 = 4/3×3.14×r^3

2240 = 4.1866r^3

r^3 = 2240/4.1866

r^3 = 534.784

r = ( 534.784 )^1/3

r = 8.1169

Since each dimension is to be multiplied by 1/4

Hence, 1/4×8.1169

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New volume will be

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V = 4/3×3.14×8.3558

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3 years ago
A postage box should weigh 1.0 pound. If there is a 5% error on the weight, what is the range of acceptable weight?
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4 (negative one-half x + 7) + 5 x = 15
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Answer:

Step 3 is incorrect

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