Answer: the following are required for IV-3 to have condition
Explanation:
-II-4 passes an X b chromosome to III-4 (probability = 1/2).
-If III-4 has the genotype X B X b (accounted for by the above probability), then she passes an X b chromosome to IV-3 (probability = 1/2).
-III-5 passes a Y chromosome to IV-3 (probability = 1/2).
All of these requirements are needed in sequence, so you apply the product rule here, too (1/2 x 1/2 x 1/2 = 1/8).
Once the individual probabilities are known, the sum and/or product rules can be used for various combinations (both conditions, either condition, etc.).
1:12 + 2:41 + 1:10 = 4 hours 63 mins
5 Hours and 3 Mins
Answer: 1/7
Explanation:
1. Use the formula, y2-y1/x2-x1
Plug in the points, (12, -8) and (-9, -11) into the formula.
Point (12, -8): 12 is the X1 and -8 is the y1.
Point (-9, -11): -9 is the X2 and -11 is the y2
So, -11--8/-9-12
2. -11--8/-9-12= -3/-21= 1/7
I hope this helps!!
Multiples of 10 = 10, 20, 30, 40, 50, 60
This means the 10th, 20th, 30th, 40th, 50th, 60th, ... fan will get a free hat.
Multiples of 12 = 12, 24, 36, 48, 60
This means the 12th, 24th, 36th, 48th, 60th, ... fan will get a free shirt.
So the 60th fan will receive both a hat and a shirt.
Meaning 60 fans will come to the stadium before a fan receives both a hat and a shirt.
<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82
3 5/24 + 6 7/24 + 4 9/24 = 13 20/24 = 13 5/6
</span><span>5 2⁄3 + 29⁄69 + 6 21⁄23 = 5 46/69 + 29/69 + 6 63/69 = 11 138/69 = 13
</span>
<span>3 9⁄10 + 4⁄9 + 7⁄45 + 4 = 3 81/90 + 40/90 + 14/90 + 4 = 7 135/90 = 8 1/2
</span><span>6 – 7⁄15 = 5 15/15 - 7/15 = 5 6/15
</span><span>11 3⁄8 – 7⁄8 = 10 11/8 - 7/8 = 10 4/8 = 10 1/2
</span><span> 7 1⁄6 – 3 4⁄9 = 7 9/54 - 3 18/54 = 6 63/54 - 3 18/54 = 3 45/54 = 3 5/6
</span>
<span>5 3⁄8 – 3 2⁄5 = 5 15/40 - 3 16/40 = 4 55/40 - 3 16/40 = 1 39/40</span>
