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Crazy boy [7]
3 years ago
8

Pls help Homework is due tomorrow and Im not sure about the answer!

Mathematics
1 answer:
____ [38]3 years ago
7 0

Answer:

The picture isn't clear enough.

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Write in simplest form. 2^9÷2^3 PLEASE HELP
Paha777 [63]

Answer:

27

Step-by-step explanation:

2x9/2x3=27

7 0
3 years ago
Read 2 more answers
The polynomial equation x^6-16x^2=4x^4-64 has complex roots +- 2i . What are the other roots? Use a graphing calculator and a sy
Irina18 [472]
Use u subsitution the solve by grouping
u=x^2
u^3-16u=4u^2-64
u^3-4u^2-16u+64=0
(u^3-4u^2)+(-16u+64)=0
u^2(u-4)+(-16)(u-4)=0
(u^2-16)(u-4)=0
(u-4)(u+4)(u-4)=0
(u+4)(u-4)^2=0

u=x^2
(x^2+4)(x^2-4)^2=0
(x^2+4)((x-2)(x+2))^2=0
(x^2+4)(x-2)²(x+2)²=0
set to zero

x^2+4=0
x^2=-4
x=+/-2i

x-2=0
x=2

x+2=0
x=-2

the other roots are -2 and 2

for graphinc calculator, graph and find x intercepts
3 0
3 years ago
Read 2 more answers
2) translate into an equation
Butoxors [25]
-4 - 7 divide 8n thats the answer
6 0
3 years ago
Please help me with this math problem
Lapatulllka [165]

Step-by-step explanation:

according to the question

55x⁶+22x⁴

11x⁴(5x²+2)

so

width:11x⁴

length:5x²+2

3 0
3 years ago
Suppose that replacement times for washing machines are normally distributed with a mean of 9.4 years and a standard deviation o
Nezavi [6.7K]

Using the normal distribution, it is found that the replacement time that separates the top 18% from the bottom 82% is of 11.23 years.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are, respectively, given by \mu = 9.4, \sigma = 2.

The desired value is the 82nd percentile, which is X when Z = 0.915, hence:

Z = \frac{X - \mu}{\sigma}

0.915 = \frac{X - 9.4}{2}

X - 9.4 = 0.915(2)

X = 11.23

The replacement time that separates the top 18% from the bottom 82% is of 11.23 years.

More can be learned about the normal distribution at brainly.com/question/24663213

6 0
2 years ago
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